Question

Joyce's dad packs her lunch and always packs a yogurt. Joyce knows that there are 5 yogurts in the refrigerator: one raspberry, two strawberry, one blueberry, and one vanilla. Her dad usually reaches into the refrigerator and randomly grabs a yogurt.



a. which flavor is she most likely to have in her lunch today?




b. What are her chances of finding a vanilla yogurt in her lunch bag?

Answer 1

Answer:

a. $Strawberry$

b. $Chances = \frac{1}{5}$

Step-by-step explanation:

Given

$Raspberry = 1$

$Strawberry = 2$

$Blueberry = 1$

$Vanilla = 1$

$Total = 5$

Solving (a): Yogurt with highest chance

From the list of given items, the number of strawberry yogurt (2) is more than any other yogurt (1 each)

This implies, She's most likely to get a strawberry than any other type

Solving (b): Chances of finding Vanilla

The chances is the same as probability

And it is calculated as thus;

$P(Vanilla) = \frac{n(Vanilla)}{Total}$

$P(Vanilla) = \frac{1}{5}$

Hence;

The chances is $\frac{1}{5}$