The lenght of the yard plus a fence around this yard will be: 50 yd+2(1.5 yd)=53 yd
The width of the yard plus a fence a fence around this yard will be: 40 yd + 2(1.5 yd)=43 yd.
Data:
New lenght (yard +fence)=53 yd
New width (yard+fence)=43 yd
Perimeter of a rectangle=2(lenght) + 2(width)
Perimeter of this yard, including the fence: 2(53 yd)+2(43 yd)=192 yd
Area of a rectangle=lenght x width
Area of this yard, including the fence:(53 yd)(43 yd)=2279 yd².
Now, we calculate the increase area percent:
1)we calculate the old area:
Data:
lenght=50 yd
width=40 yd
Old area=(50 yd)(40 yd)=2000 yd²
2)we calculate: How many yards² has the area of the yard increased?
Yards gained=2279 yd² - 2000 yd²=279 yd².
3) Now, at last, What percent did the area increase:
2000 yd²-------------------------------100%
279 yd²---------------------------------- x
x=(279 yd² * 100%) / 2000 yd²=13.95%
Answer:The perimeter of the yard, including the fence would be 192 yd, the area of the yard, including the fence would be 2279 yd², and the percent of the area increase would be: 13.95%.
