Question

ground-state electron configuration for an atom of selenium

Answer 1

Answer:

1s22s22p63s23p64s23d104p4

Explanation:

Answer 2

The ground-state electronic configuration of Selenium is:

$[Se]= 1s^22s^22p^63s^23p^63d^{10}4s^24p^4$

Explanation:

• The electronic configuration of an element is an arrangement of its electrons in different energy levels around the atomic nucleus.
• And the electronic configuration in which the arrangement of electrons is with lower energy levels around the nucleus is termed as ground-state electronic configuration.
• It is written with help of an atomic number of an element.

Given:

The element selenium.

To find:

The electronic configuration of selenium

Solution:

In the modern periodic table, Selenium has the atomic number of  34.

The number of protons in selenium = Atomic number = 34

Number of electrons in selenium = Number of protons in selenium = 34

There are 34 electrons in atom selenium and they will be filled according to the Aufbau rule that the electron will be filled in a subshell with lower orbital energy.  

The electronic configuration of Selenium:

$[Se]= 1s^22s^22p^63s^23p^63d^{10}4s^24p^4$

or

$[Se]=[Ar]3d^{10}4s^24p^4$

So, the ground-state electronic configuration of Selenium:

$[Se]= 1s^22s^22p^63s^23p^63d^{10}4s^24p^4$

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