Respuesta :

Answer:

[tex] \frac{1}{2} [/tex]

Step-by-step explanation:

To find the ratio of AP/PB, find the distance between A and P, then P and B.

Distance between A(-5, 6) and P(1, 4):

[tex] AP = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

[tex] A(-5, 6) = (x_1, y_1) [/tex]

[tex] P(1, 4) = (x_2, y_2) [/tex]

[tex] AP = \sqrt{(1 -(-5))^2 + (4 - 6)^2} [/tex]

[tex] AP = \sqrt{(6)^2 + (-2)^2} [/tex]

[tex] AP = \sqrt{36 + 4} = \sqrt{40} [/tex]

Distance between P(-1, 2) and B(1, -2):

[tex] PB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

[tex] P(1, 4) = (x_1, y_1) [/tex]

[tex] B(13, 0) = (x_2, y_2) [/tex]

[tex] PB = \sqrt{(13 - 1)^2 + (0 - 4)^2} [/tex]

[tex] PB = \sqrt{(12)^2 + (-4)^2} [/tex]

[tex] PB = \sqrt{144 + 16} = \sqrt{160} [/tex]

[tex] \frac{AP}{PB} = \frac{\sqrt{40}}{\sqrt{160}} [/tex]

[tex] = \frac{\sqrt{40}}{2\sqrt{40}} [/tex]

[tex] = \frac{1}{2} [/tex]

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