Answer:
[tex]F=\dfrac{9}{5}(K-273.15)+32[/tex]
Step-by-step explanation:
Undo the various operations done to F.
[tex]K=\dfrac{5}{9}(F-32)+273.15\quad\text{given}\\\\K-273.15=\dfrac{5}{9}(F-32)\quad\text{subtract 273.15}\\\\\dfrac{9}{5}(K-273.15)=F-32\quad\text{multiply by 9/5}\\\\\boxed{F=\dfrac{9}{5}(K-273.15)+32}\quad\text{add 32}[/tex]
