A drone drops a package on a target from a height of 2.40\,\text m2.40m2, point, 40, start text, m, end text. The drone is traveling horizontally at a speed of 1.50\,\dfrac{\text m}{\text s}1.50 s m ​ 1, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction.

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Answer:

1.05m

Explanation:

To get this answer, you must first know how long it takes the ball to reach the ground. In order to figure that out, the process is simple:

First: Multiply the object's height by 2.

2.4x2=4.8

Next: Divide that answer by the speed of Gravity, 9.8 or 9.81m/s^2

(I prefer to use the method used by engineers, attend to precision, so I keep the same number of decimals in each number I am calculating.)

4.8/9.8=0.48979591836734693877551020408163m/s^2

Next: Square Root this answer.

=0.69985421222376517091350973563025

Last: Multiply your square rooted answer by your  forward velocity.

0.69985421222376517091350973563025x1.5=

1.0497813183356477563702646034454 or, since Khan Academy only wants three significant digits, round up to 1.05.

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Answer:

1.05m

Explanation:

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