Question

The literature value for the density of aluminum is 2.6 g/mL. If an experimenter
calculates a value of 2.2 g/mL, what is their percent error?

Answer 1

Answer:

The answer is

15.38%

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\%$

From the question

actual density = 2.6 g/mL

error = 2.6 - 2.2 = 0.4

The percentage error is

$P( \% ) = \frac{0.4}{2.6} \times 100 \\ = 15.384615...$

We have the final answer as

15.38%

Hope this helps you