Question

An aquarium has a base in the shape of a trapezoid. The base is 90 cm long at the front, 60 cm long at the back, and 30 cm wide (from front to back). The height is 100 cm. What is the volume of the aquarium in litres?

Answer 1

Answer:

Step-by-step explanation:

First calculate for the area of the trapezoid (the formula is (base + base / 2) x height):

60 cm + 90 cm = 150 cm

150 cm / 2 = 75 cm

75 cm x 30 cm = 2250 cm²

Now 1 cm² = 1 mL and 1000 mL = 1 L

2250 cm² = 2250 mL

2250 mL = 2.25 L

Answer 2

The volume of the aquarium of height 100 cm and area of 2250 cm sq is 225L.

An aquarium has a trapezoid base. The base is 90 cm long at the front, 60 cm long at the back, and 30 cm wide (from front to back). The height is 100 cm.

What is the area of the trapezoid and volume of the trapezoid?

The area of the trapezoid is calculated by measuring the sum of the parallel sides divided by 2 and multiplying it with its height.

A = [(a + b)/2] × h

The volume of the trapezoid is the product of the area of the trapezoid and the height between the trapezoid's end.

The volume of trapezoid = area × height between trapezium ends

so, the area of the trapezoid, A = [ 90 + 60 ]/2 × 30

= 150 /2 × 30

= 75 × 30

= 2250 $\rm cm^{2}$

The volume of trapezoid = area × height between trapezium ends

The volume of the trapezoid = 2250 × 100

                                                = 225000 $\rm cm^{3}$

Now, 1 cm² = 1 mL and 1000 mL = 1 L

225000 cm² = 225000mL

225000 mL = 225 L

Therefore, the volume of the aquarium of height 100cm and area of 2250 cm sq is 225L.

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