Question

What is 4 over 9, to the power of negative a half? - Can you also give an
explanation of how to do it?

Answer 1

So, We Have:
$(\frac{4}{9}) ^{ (-\frac{1}{2}) }$
We Know that Negative Exponents Equal Division.  So:$\frac{4}{9}^{( -\frac{1}{2} )} = \frac{1}{ \sqrt[]{ \frac{4}{9} } } = \frac{1}{ (\frac{2}{3} )} = \frac{3}{2} = 1.5$
I Hope This Helps!