Question

Micah's gym is moving into a bigger space, where he can have more stationary bicycles and treadmills. Micah needs both stationary bicycles and treadmills in his gym.

Let x be the number of bicycles and y be the number of treadmills.

The number of new bicycles must be more than 13 times the number of new treadmills. Each bicycle costs $340 and each treadmill costs $670. He must spend less than $5,650.

Select all of the constraints for this situation.

Answer 1

Answer:

Options (2), (3), (5) and (6)

Step-by-step explanation:

Let the number of bicycles = x

and the number of treadmills = y

Since, number of new bicycles must be more than $\frac{1}{3}$ times of new treadmills,

Inequality representing the statement will be,

x > $\frac{1}{3}$y

Each bicycle costs $340 and each treadmill costs $670.He must spend less than $5650,

Inequality will be,

340x + 670y < 5650

And the number of bicycles and treadmills should be greater than 0.

x > 0

y > 0

Therefore, constraints for this situation are,

Option (2)

Option (3)

Option (5)

Option (6)

Answer 2

naw i just did the test the correct options are 1, 2, 3, and 6 I promise

look at the capture to see the proof