Answer:
The listener is approximately 71.414 feet far from the whisperer.
Step-by-step explanation:
We must remember that two fundamental variables for every ellipse are the major semiaxis ([tex]a[/tex]) and the minor semiaxis ([tex]b[/tex]). The major semiaxis equals a half of the length of the whispering gallery, whereas the minor semiaxis equals a half of the width of the whispering gallery. These are:
[tex]a = 46\,ft[/tex] and [tex]b = 29\,ft[/tex]
The distance between both whisperers ([tex]d[/tex]), measured in feet, is two times the distance between center and any of the foci ([tex]c[/tex]), measured in feet, whose valued is obtained by using this Pythagorean identity:
[tex]d = 2\cdot c[/tex]
[tex]c = \sqrt{a^{2}-b^{2}}[/tex]
If [tex]a = 46\,ft[/tex] and [tex]b = 29\,ft[/tex], then:
[tex]c = \sqrt{(46\,ft)^{2}-(29\,ft)^{2}}[/tex]
[tex]c \approx 35.707\,ft[/tex]
[tex]d = 2\cdot (35.707\,ft)[/tex]
[tex]d = 71.414\,ft[/tex]
The listener is approximately 71.414 feet far from the whisperer.