Question

Jeremy wants to determine the number of solutions for the equation below without actually solving the equation. Negative 3 (x + 1) + 3 x = negative 3 (x minus 1) + 3 Which method should Jeremy use? Determine whether the equation has the form a = a, and if it does, the equation has infinitely many solutions. Determine whether the equation has the form a = b, and if it does, the equation has no solution. Determine whether the equation has the form x = a, and if it does, the equation has one solution. Determine whether the equation has the form x = 0, and if it does, the equation has no solution.

Answer 1

Answer:

The correct option is (c).

Step-by-step explanation:

The equation to be solved is:

$-3(x+1)+3x=-3(x-1)+3$

The expression consist of only one variable, i.e. x.

So, to compute the value of this variable the equation has to be reduced to the form:

x = a

Thus, the correct option is (c).

Solve the equation as follows:

$-3(x+1)+3x=-3(x-1)+3$

$-3x-3+3x=-3x+3+3\\-3=-3x+6\\3x=6+3\\3x=9\\x=3$

Answer 2

Answer:

C

Step-by-step explanation: