PLEASE HURRY in below diagram, line bc is parallel to de. i.e bc de abc=47 cab=105 find cae

Answer:
[tex]\angle CAE=28[/tex]
Step-by-step explanation:
[tex]\angle CBA+\angle BAE=180\\\\\angle CBA+\angle BAC+\angle CAE=180\\\\47+105+?=180\\\\152+?=180\\\\?=28[/tex]