Given:
A six-sided die is tossed 4 times.
To find:
The probability of observing four ones in a row.
Solution:
If a six-sided die is tossed 4 times, then the total number of outcomes is
[tex]\text{Total outcomes}=6\times 6\times 6\times 6=1296[/tex]
Four ones in a row means getting 1 in all four tosses, i.e., 1111.
[tex]\text{Favorable outcomes}=1[/tex]
Now,
[tex]Probability=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]
[tex]Probability=\dfrac{1}{1296}[/tex]
Therefore, the required probability is [tex]\dfrac{1}{1296}[/tex].