Respuesta :

msm555

Answer:

Solution given:

4x²+35x-9=0

comparing above equation with ax²+bx+c.

we get

a=4

b=35

c=-9

we have

x=[tex] \frac{ - b±\sqrt{b²-4ac}}{2a} [/tex]

x=[tex] \frac{ - 35±\sqrt{35²-4*4*-9}}{2*4} [/tex]

x=[tex] \frac{ - 35±\sqrt{1369}}{2*4} [/tex]

x=[tex] \frac{ - 35±37}{8} [/tex]

taking positive;

x=[tex] \frac{ - 35+37}{8} [/tex]

x=[tex] \frac{1}{4} [/tex]

taking negative

x=x=[tex] \frac{ - 35-37}{8} [/tex]

x=-9

Therefore:the roots of 4+ 35x − 9 = 0 is [tex] \frac{1}{4} [/tex] or-9.

  • 4x²+35x-9=0
  • 4x²+36x-x-9=0
  • 4x(x+9)-1(x+9)=0
  • (4x-1)(x+9)=0
  • x=1/4 and -9
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