Answer:
Step-by-step explanation:
Slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by the formula,
Slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Slope of the line PQ passing through the two points P(-8, 2) and Q(4, 2) will be,
Slope '[tex]m_1[/tex]' = [tex]\frac{2-2}{-8-2}[/tex] = 0
Therefore, slope of the line PQ parallel to the x-axis = 0
Slope of the line MN passing through the points M(8, 6) and N(8, -8) is,
Slope '[tex]m_2[/tex]' = [tex]\frac{6+8}{8-8}[/tex] = ∞
Therefore, slope of the line MN parallel to y-axis is undefined.
Since, angle between the x-axis and y-axis is 90°,angle at the intersection point between the lines parallel to x and y axis will be 90°.
These lines are perpendicular to each other.
