Find the 12th term of the geometric sequence 1, 3, 9, ...

Answer:
177147
Step-by-step explanation:
The n th term of a geometric sequence is
[tex]a_{n}[/tex] = a[tex]r^{n-1}[/tex]
where a is the first term and r the common ratio
Here a = 1 and r = 3 ÷ 1 = 3 , thus
[tex]a_{12}[/tex] = 1 × [tex]3^{11}[/tex] = 177147
The 12th term of the geometric sequence ( 1, 3, 9, . . . ) is 177147.
The nth term of a geometric sequence is expressed as;
nth = arⁿ⁻¹
Where a is the first term and r is the common ratio.
Given that;
nth = arⁿ⁻¹
12th = 1 × 3¹²⁻¹
12th = 1 × 3¹¹
12th = 1 × 177147
12th = 177147
Therefore, the 12th term of the geometric sequence ( 1, 3, 9, . . . ) is 177147.
Learn more about geometric series here: brainly.com/question/19458543
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