Question

How long must a tow truck apply a force of 550 N to increase the speed of a 1,200 kg car at
rest to 2 m/s?

Answer 1

Answer:

F=m[vf-vi]/t

t=m[vf-vi]/F

t=[1200][2]/[550]

t=4.36s

Explanation:

Answer 2

A tow truck will take 4.36 s.

Given:

Force, F= 550N

Mass, m= 1200kg

Final Velocity vf= 2 m/s

Initial Velocity vi= 0 m/s

A force can cause an object with mass to change its velocity (e.g. moving from a state of rest), i.e., to accelerate.

$F= m*a$...............(i)

and $a=\frac{[v_f-v_i]}{t}$...............(ii)

So, on substituting (ii) in (i)

$F=\frac{m[v_f-v_i]}{t} \\\\t= \frac{m[v_f-v_i]}{F}\\\\t= \frac{[1200][2-0]}{[550]} \\\\t=4.36s$

Thus, time taken is 4.36 s.

Learn more:

brainly.com/question/18038995