Question

a stadium has 55,000 seats. seats sell for $25 in section A, $20 in section B, and $15 in section C. the number of seats in section A equals the total number of seats in sections B and C. suppose the stadium takes in $1,174,000 from each sold-out event. how many seats does each section hold?

Answer 1

Answer:

A=number of seats in section A

B=number of seats in section B

C=number of seats in section C

Step-by-step explanation:

We can suggest this system of equations:

A+B+C=55,000

A=B+C                                      ⇒A-B-C=0

28A+16B+12C=1,158,000

We solve this system of equations by Gauss Method.

1             1              1               55,000

1            -1            -1                         0

28         16           12          1,158,000  

1             1              1               55,000

0            -2             -2             -55,000                                    (R₂-R₁)

0           12             16           382,000                                    (28R₁-R₂)  

1            1                1              55,000

0           -2              -2             -55,000

0            0                4               52,000                                     (6R₂+R₃)

Therefore:

4C=52,000

C=52,000/4

C=13,000

-2B-2(13,000)=-55,000

-2B-26,000=-55,000

-2B=-55,000+26,000

-2B=-29,000

B=-29,000 / -2

B=14,500.

A + 14,500+13,000=55,000

A+27,500=55,000

A=55,000-27,500

A=27,500.

Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.