Answer:
[tex]\angle B=23.96\\\\\angle C=59.04[/tex]
Step-by-step explanation:
[tex]\:The\:law\:of\:sines\:is:\\\\\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}[/tex]
[tex]with\\\\A=97\\\\a=22\\\\b=9\\\\c=19[/tex]
[tex]so\:we\:have\\\\\frac{\sin 97}{22}=\frac{\sin B}{9}\\\\\sin B=\frac{9\sin 97}{22}\\\\B=\sin^{-1}(\frac{9\sin 97}{22})\\\\B\approx 23.96[/tex]
[tex]You\:could\:use\:the\:law\:of\:sines\:again\\\\But\:remember\:that\:the\:sum\:of\:angles\:is\:180\\\\\angle A+\angle B+\angle C=180\\\\97+23.96+\angle C=180\\\\120.96+\angle C=180\\\\\angle C=59.04[/tex]
