Little help please? It would be much appreciated :D

Answer:
[tex]\frac{12ac^1^4}{b^3}[/tex]
Step-by-step explanation:
[tex]\frac{(a^{2}b^{4}c)^2 (6a^3b)(2c^5)^3}{4a^6b^1^2c^3}[/tex]
[tex]\frac{(a^4b^8c^2)(6a^3b)(8c^1^5)}{4a^6b^1^2c^3}[/tex]
[tex]\frac{48a^{7}b^9c^1^7}{4a^6b^1^2c^3}[/tex]
[tex]\frac{12ac^1^4}{b^3}[/tex]