20 POINTS! ASAP PLS! Show work!!

Hi there.
Recall that:
csc θ = 1 / (sin θ) - deals with y-values
sec θ = 1 / (cos θ) - deals with x-values
If csc θ < 0, then the y-coordinate of the angle must be negative.
If sec θ > 0, then the x-coordinate of the angle must be positive.
The quadrant on the coordinate plane that consists of negative y-coordinates and positive x-coordinates is the 4th quadrant.
Answer:
QIV
Step-by-step explanation:
To answer this question, we can use the standard ASTC acronym.
This stands for: All Students Take Calculus.
The first letter of each word tells us what is positive in each quadrant.
So, in QI, all trig ratios are positive.
In QII, only sine ( and cosecant) is positive.
In QIII, only tangent (and cotangent) is positive.
And in QIV, only cosine (and secant) is positive.
We know that csc(θ)<0. In other words, csc(θ) is negative.
Since csc(θ) is negative, sin(θ) is also negative.
So, our θ can't be in QI or QII.
We also know that sec(θ) is positive.
Our θ can only either be in QIII or QIV.
In QIII, only tangent is positive, so cosine will be negative.
So, θ is not in QIII.
So, the only choice that remains is QIV. And cosine and secant are indeed positive in QIV.
So, our angle θ is in QIV.
And we're done!