Respuesta :
Answer: (1, √15) and (1, -√15)
Step-by-step explanation:
A circle centered at the point (a, b) of radius R can be written as:
(x - a)^2 + (y - b)^2 = R^2
In this case we have:
"A circle is centered at the origin (0,0) and has a radius of 4 units"
Then the equation for this circle is:
x^2 + y^2 = 4^2 = 16.
Now, we want to find the points where x = 1, then we can replace that value and solve the equation for y.
1^2 + y^2 = 16
1 + y^2 = 16
y^2 = 16 - 1 = 15
y = +-√15
Then the two points that have the x-coordinate equal to 1 are:
(1, √15) and (1, -√15)
The points on the circle which have an x-coordinate of 1 are:. (1,+√15) and (1,-√15)
The equation of a circle usually takes the form;
- (x-a)² + (y-b)² = r²
where a and b are x- and y- coordinates of the center of the circle.
In this scenario, the center is at the origin (0,0).
In essence, the points on the circle which have an x-coordinate of 1 can be evaluated as follows;
- (1-0)² + (y - 0)² = 4²
- 1 + y² = 16.
- y² = 15
- y = ±√15.
The points on the circle which have an x-coordinate of 1 are:. (1,+√15) and (1,-√15)
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