Respuesta :

Answer:

The unknown angle =

27°

Note :

SOH = Sin angle = Opposite/hypotenuse

CAH = Cos angle = Adjacent/Hypotenuse

TOA = Tan angle = Opposite/Adjacent

Ver imagen ZJSG09112007

Answer:

[tex]\theta \approx 27.5\º[/tex]

Step-by-step explanation:

Once

[tex]$\sin(\theta) = \dfrac{\text{Opposite}}{\text{hypotenuse}} =\frac{12}{26}=\frac{6}{13} $[/tex]

And

[tex]\arcsin \left(\dfrac{6}{13} \right)=\theta[/tex]

[tex]\theta \approx 27.5\º[/tex]

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