Question

A 500 g block of metal absorbs 5016 J of heat when its temperature changes from 20.0°C to 30.0°C. Calculate the specific heat of the metal.

Answer 1

Explanation:

the answer is

s= 1.0032 J/ g .C

Answer 2

The specific heat of the metal is  1.0032 J/ g .C.

What is specific heat?

The quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree.

• The formula is Cv = Q / (ΔT ⨉ m)
• Here,  Q = absorbed heat = 5016 J
• Mass m = 500g
• ΔT = t1 - t2 = 30 - 20 = 10°C

Putting above values in the equation we get,

      Cv = 5016/(500 x 10)

      Cv = 5016/5000

      Cv = 1.0032J/g .C

Thus , the specific heat of the metal is  1.0032 J/ g .C.

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