Use the quadratic formula to find the solutions.
−
b
±
√
b
2
−
4
(
a
c
)
2
a
-
b
±
b
2
-
4
(
a
c
)
2
a
Substitute the values
a
=
5
a
=
5
,
b
=
−
15
b
=
-
15
, and
c
=
−
50
c
=
-
50
into the quadratic formula and solve for
x
x
.
15
±
√
(
−
15
)
2
−
4
⋅
(
5
⋅
−
50
)
2
⋅
5
15
±
(
-
15
)
2
-
4
⋅
(
5
⋅
-
50
)
2
⋅
5
Simplify.
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x
=
3
±
7
2
x
=
3
±
7
2
The final answer is the combination of both solutions.
x
=
5
,
−
2
