Question

A sandbox has an area of 26 square feet, and the length is 5-1/2 feet. What is the width of the sandbox?

Answer 1

(5 1/2) x width = 26;
Then, (11/2) x width = 26;
width = 26 ÷ (11/2);
width = (26x2)/11;
width = 52/11 = 4.72 feet;

Answer 2

Answer:

Width of the sandbox, b = 4.72 feet

Step-by-step explanation:

It is given that,

The area of the sandbox, $A=26\ ft^2$

Length of the box, $l=5\dfrac{1}{2}\ ft=5.5\ ft$

We need to find the width of the sandbox. The area of the rectangle is given by :

$A=l\times b$

b is the width of the sandbox

So, $b=\dfrac{A}{l}$

$b=\dfrac{26}{5.5}$

b = 4.72 feet

So, the width of the sandbox is 4.72 feet. Hence, this is the required solution.