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What does integers have to do with Square Roots?

x-34=xy=78

[tex]\sqrt{x}[/tex] = 91,xy=t

Please Help no dumb answers please. :)

Respuesta :

From the examples given it is unclear.

If you know that the square root of some number, x, is 91, you can square 91 to find the value of x.

91² = 8281. Both numbers are integers. 91 can be factored-- 91=7 × 13. Both are prime factors and integers, but not square roots of 91

-34 is an integer, factors could be -2 and 17 or -17 and 2 prime factors and integers. But the square root of -34 is an imaginary number.

78 is not a multiple of -34 so if you are trying to get factors xy of 78 and -34, at least one factor will not be an integer, and the square root is probably irrational-- not an integer.

Maybe confusing, but I'm attempting a sensible discussion of the question.

Answer:

An integer is either a perfect square or its square root is irrational. Said a different way, when you compute the square root of an integer, there are either no figures to the right of the decimal or there are an infinite number of figures to right of the decimal and they don't repeat

Step-by-step explanation:

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