contestada

2Ca3(PO4)2 + 6SiO2 + 10C --> P4 + 6CaSiO3 + 10CO how many grams of calcium phosphate are required to give 30.0g of phosphorus?? I got 542g but I think that is way off. I did 30g P/30.97g to get .989 moles P • 2Ca= 1.94 mole Ca• 279.21g to get from miles to grams. Please explain how to do it and if you can where I went wrong.

Respuesta :

Yipes

2mol                             :           1mol
2Ca₃(PO₄)₂ + 6SiO₂ + 10C ⇒    P₄      + 6CaSiO₃ + 10CO
620g                             :            124g
x                                   :             30g

[tex]x=\frac{30g*620g}{124g}=150g[/tex]

Otras preguntas