Question

Find the distance between the two points rounding to the nearest tenth (if necessary).
(3, -6) and (-3,2)

Answer 1

Answer:

d=7.2

Step-by-step explanation:

We can use the Pythagoras theorem to solve for the answer.

step one:

given that the points are located at (x1,y1),(x2,y2) =(3, -6) and (-3,2)

$d=\sqrt{(x2-x1)^2-(y2-y1)^2}$

step two:

substituting into the formula we have

$d=\sqrt{(-3-3)^2+(2-(6))^2} \\\\d=\sqrt{(-6)^2+(2+6))^2} \\\\d=\sqrt{(36+(-4)^2} \\\\d=\sqrt{(36+16} \\\\d=\sqrt{52} \\\\\\d=7.211$

To the nearest tenth we have

d=7.2