Respuesta :
Answer:
- 2 +i
- 2 -i
Step-by-step explanation:
For ax²+bx+c = 0, the solutions are ...
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
For the given quadratic term, a=1, b=-4, c=5, so the solutions are ...
[tex]x=\dfrac{-(-4)\pm\sqrt{(-4)^2-4(1)(5)}}{2(1)}=\dfrac{4\pm\sqrt{-4}}{2}\\\\\boxed{x=2\pm i}[/tex]
Answer:
-2i+1 and 2-i
Step-by-step explanation:
Got it right on edge