The freezing temperature of the water is 32 degrees Fahrenheit and the boiling temperature of water is 212 degrees Fahrenheit. Write an absolute value equation that represents the minimum and maximum temperature of liquid water. Use X to represent the temperature.

Respuesta :

Answer:

90 = | x - 122 |

Step-by-step explanation:

Given;

maximum temperature, 212 °F

minimum temperature, 32 °F

First, determine the difference of both values;

212 - 32 = 180

Divide this value by 2

180/2 = 90

90 = | x - 212 + 90|

90 = | x - 122 |

where;

x is the temperature of water

Thus, the absolute value equation that represents the minimum and maximum temperature of liquid water is 90 = | x - 122 |

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