Question

Please help this sat math problem got me stumped

Answer 1

2^12 :)

You can re-write the fraction as:
((2^3)^x) / 2^y

Rule for dividing powers gives us:
2^(3x-y)

But we know 3x-y=12, so answer A
Let me know if you want workings out on paper :)

Answer 2

Answer:

option A

Step-by-step explanation:

$3x-y=12\\ =>3x = 12+y\\=>x=\frac{y+12}{3}$

Putting the value of x in $\frac{8^{x} }{2^{y} }$ gives :-

$\frac{8^\frac{y+12}{3} }{2^y} = \frac{2^3(\frac{y+12}{3} )}{2^y} = \frac{2^{y+12} }{2^y} = 2^{y+12-y}=2^{12}$