HELPP!!what is the answer to this picture above^
![HELPPwhat is the answer to this picture above class=](https://us-static.z-dn.net/files/d36/f4b33e6433f13665eb88ae92fbaacd25.png)
Answer:
[tex] \fbox{ \fbox { \sf{Distance = \sf{15 \: units}}}}[/tex]
[tex]{ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}[/tex]
Step-by-step explanation:
[tex] \star{ \: \sf { \: Let \: the \: points \: be \: A \: and \: B}}[/tex]
[tex] \star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}[/tex]
[tex] \underline{ \underline{ \tt{Finding \: the \: distance}}}[/tex]
[tex] \boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}[/tex]
[tex] \mapsto{ \sf{Distance = \sqrt{ {(18 - 6)}^{2} + {(15 - 6)}^{2} } }}[/tex]
[tex] \mapsto{ \sf{Distance = \sqrt{ {(12)}^{2} + {(9)}^{2} } }}[/tex]
[tex] \mapsto{ \sf{Distance = \sqrt{144 + 81}}} [/tex]
[tex] \mapsto{ \sf{Distance = \sqrt{225} }}[/tex]
[tex] \mapsto{ \sf{Distance = \sqrt{ {15}^{2} } }}[/tex]
[tex] \mapsto{ \boxed{\sf{Distance = 15 \: units}}}[/tex]
[tex] \underline{ \underline {\tt{Finding \: the \: Midpoint}}}[/tex]
[tex] \boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}[/tex]
[tex] \mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2} \: , \: \frac{6 + 15}{2} )}}[/tex]
[tex] \mapsto{ \sf{Midpoint = ( \frac{24}{2} \: , \: \frac{21}{2} )}}[/tex]
[tex] \mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}[/tex]
Hope I helped!
Best regards! :D
~[tex] \sf{TheAnimeGirl}[/tex]