Question

what’s the distance between 4,-2 and 6,-1

Answer 1

Answer:

√5

Step-by-step explanation:

$( 4,-2 )=(x_1,y_1)\\( 6,-1)=(x_2,y_2)\\\\d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\\d =\sqrt{\left(6-4\right)^2+\left(-1-\left(-2\right)\right)^2}\\\\d=\sqrt{\left(6-4\right)^2+\left(-1+2\right)^2}\\\\d=\sqrt{2^2+1^2}\\\\d =\sqrt{4+1}\\\\d=\sqrt{5}$

Answer 2

Hello! I hope this helps