Answer:
The answer is
10.2 units
Step-by-step explanation:
The distance between two points can be found by using the formula
[tex]d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\ [/tex]
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
P(-4,3) and Q(6,1)
The distance between them is
[tex] |PQ| = \sqrt{ ({ - 4 - 6})^{2} + ({3 - 1})^{2} } \\ = \sqrt{ ({ - 10})^{2} + {2}^{2} } \\ = \sqrt{100 + 4} \: \: \: \: \: \: \: \: \: \\ = \sqrt{104} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 2 \sqrt{26} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 10.1980390271[/tex]
We have the final answer as
10.2 units to the nearest tenth
Hope this helps you
