Answer:
Step-by-step explanation:
1). If a point C is lying on a line segment RB,
Then RB = RC + CB
Since, RB = 45, CB = 3x - 12 and RC = 2x + 9
45 = (2x + 9) + (3x - 12)
45 = (2x + 3x) - 3
48 = 5x
x = [tex]\frac{48}{5}[/tex]
x = 9.6
2). Since, RC = 2x + 9
RC = 2(9.6) + 9
= 19.2 + 9
= 28.2 units
3). Distance between the two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by the formula,
d = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Distance between the points A(2, -2) and D(-2, 2) will be,
[tex]AD=\sqrt{(2+2)^2+(-2-2)^2}[/tex]
= [tex]\sqrt{16+16}[/tex]
= [tex]4\sqrt{2}[/tex]
= 5.657
≈ 5.66 units