Answer:
Perimeter of the dog park = 15.4 yards
Step-by-step explanation:
Coordinates of the vertices of the given triangle are,
P(1, 2), Q(1, 6), R(-4, 2)
Since distance between the two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] is,
d = [tex]\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
Length of PQ = [tex]\sqrt{(1-1)^2+(2-6)^2}[/tex]
PQ = 4
Length of PR = [tex]\sqrt{(1+4)^2+(2-2)^2}[/tex]
PR = 5
Length of QR = [tex]\sqrt{(1+4)^2+(6-2)^2}[/tex]
QR = [tex]\sqrt{25+16}[/tex]
= [tex]\sqrt{41}[/tex]
= 6.4 yards
Therefore, perimeter of the given triangle = PQ + QR + PR
= 4 + 6.4 + 5
= 15.4 yards