Question

The electrostatic force between two charges is originally F. Which expression represents the new electrostatic force between the two charges if one charge doubles and the other one is divided by three?
• 1/6
• 3/2
• 2/3
• 6

Answer 1

Answer: c)• 2/3

Explanation:

Lets say q1 and q2 are two charges with r distance far apart.

So electrostatic force

F = (k q1 q2) / r²

as k = Coulomb's constant

Now

q1' = 2q1

q2' = q2/3

Therefore the new electrostatic force

F' = (k q'1 q'2) / r²

F' = (k 2q1 q2) / 3r²

F' = 2/3 [(k q1 q2) / r²]

so F' = 2/3F

New electrostatic force  is 2/3F

Answer 2

The expression that represents the new electrostatic force between the two charges if one charge doubles and the other one is divided by three is;

Option C; F_new = ²/₃F

Formula for electrostatic force is;

F = kq₁q₂/r²

where;

k = Coulomb's constant

q₁ = first charge

q₂ = second charge

r = distance between charges

Now, we are told that one charge doubles and the other one is divided by three. Thus, the new charges are now;

2q₁ and q₂/3

Thus;

F_new = k(2q₁ × q₂/3) / r²

F_new = ²/₃kq₁q₂/r²

F_new in terms of F is;

F_new = ²/₃F

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