Question

Calculate the mass of NaOH required to make 300 CM3 of 0.2M solution​

Answer 1

Answer:

Mass of NaOH = 2.4 grams

Explanation:

$M\:=\:\frac{n}{v}$

where,

$n=moles\:of\:solute$

$v=liters\:of\:solution$

Remember:    $\quad 1000\:cm^3=1\:L$

$\Rightarrow \quad 300\:cm^3=0.3\:L$

$n=\frac{m}{40\:g/mol}$

Putting the values, we have:

$0.2=\frac{m}{40\:g/mol}\times \frac{1}{0.3}$

$\Rightarrow m=2.4\:g$

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