Question

A stone is thrown vertically with a speed of 5m/s. It came back to thrower in 20sec. Calculate the maximum height it reaches​

Answer 1

Hi There Buddy!

Lets make use of the equations of motion to solve this problem.

We know time of flight is 2u/g

===> 2u/10 = 20 =====> u = 100 m/s

Now, we know the initial velocity, we have to find the maximum height.

H = (u^2)/2g = 10^4 / 20 = 500 m