Answer:
y=(x+1)^2
Step-by-step explanation:
we have the following
[tex]x=1;y=4\\\\x=2;y=9\\\\x=3;y=16\\\\x=4;y=25[/tex]
the values of y are squares so we can write
[tex]x=1;y=2^{2} \\\\x=2;y=3^2\\\\x=3;y=4^2\\\\x=4;y=5^2[/tex]
so as you can see when
[tex]x=n;y=(n+1)^2[/tex]
so our relation is
[tex]y=(x+1)^2[/tex]