Please Help!!!!!!
a.Two members of the Math Competition Team solve 13 problems in 1 hour. Assume all team members solve problems at the same rate. How many team members are needed to solve in 1 hour: 91 problems
b. Two members of the Math Competition Team solve 13 problems in 1 hour. Assume all team members solve problems at the same rate. How many team members are needed to solve in 1 hour:
195 problems?

Respuesta :

Answer:

a=14

Step-by-step explanation:

I only have the answer for A.

Step 1: What we need to do is divide 91 by 13: 91/13=7

Step 2: Multiply 7 by 2 becasue there were 2 members in the beginning. 7*2=14

There you have your answer: a=14

It will need 14 team members to solve 91 problems in 1 hour.

It will need 30 team members to solve 91 problems in 1 hour.

Given that,

Two members of the Math Competition Team solve 13 problems in 1 hour. Assume all team members solve problems at the same rate.

We have to determine,

How many team members are needed to solve in 1 hour: 91 problems.

How many team members are needed to solve in 1 hour: 195 problems.

According to the question,

  • To solve in 1 hour: 91 problems team members are needed = Two members team solve 13 problems in 1 hour.

Then,

[tex]\dfrac{91}{13}= 7 \ problems\ per \ 2 \ members[/tex]

Two member per 7 problems = (7).(2) = 14

It will need 14 team members to solve 91 problems in 1 hour.

  • To solve in 1 hour: 195 problems team members are needed = Two members Team solve 13 problems in 1 hour.

Then,

[tex]\dfrac{195}{13}= 15 \ problems\ per \ 2 \ members[/tex]

Two member per 15 problems = (15).(2) = 30

It will need 30 team members to solve 195 problems in 1 hour.

To know more about Multiplication click the link given below.

https://brainly.com/question/14933926

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