Question

A fire truck is responding to an emergency it accelerates from 0 to 66 km/hour in 11 seconds what is its rate of acceleration?

Answer 1

Answer:

$a=1.67\frac{m}{s^2}$

Explanation:

Hello,

In this case, since the acceleration is defined as the velocity change from final to initial divided by the time:

$a=\frac{v_f-v_0}{t}$

We obtain it with the proper units:

$v_f=66\frac{km}{h} *\frac{1h}{3600s}*\frac{1000g}{1km}=18.3\frac{m}{s}$

$a=\frac{18.3\frac{m}{s} -0\frac{m}{s} }{11s} \\\\a=1.67\frac{m}{s^2}$

Best regards.