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What is the approximate density of a mineral with a mass of 262.2 grams that displaces 46 cubic centimeters of water?

Respuesta :

Step-by-step explanation:

density = mass/ volume

= 262.2grams/46cm³

= 5.7grams per cubic centimeters approximately 6cm³

The approximate density of a mineral is 5.7  [tex]\frac{g}{cm^{3} }[/tex].

What is density?

"The density of an object is the mass of the object compared to its volume. The equation for density is: Density = mass/volume."

Given

Mass (m)=262.2 g

V=46 cm3

density (d) = ?

The volume of the mineral is equal to the volume of water it displaced, because the density of water is 1 g/cm3

Formula for density is

d = [tex]\frac{m}{V}[/tex]

= [tex]\frac{262.2 g }{46 cm^{3} }[/tex]

= 5.7 [tex]\frac{g}{cm^{3} }[/tex]

Hence, the approximate density of a mineral is 5.7  [tex]\frac{g}{cm^{3} }[/tex].

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