Question

A motorcycle moving at 40 m/s accelerates at -6.0 m/s2 for 4.0 seconds. What is the motorcycle's velocity at the end of this 4.0 second interval?​

Answer 1

Answer:

16 m/s

Explanation:

Given:

v₀ = 40 m/s

a = -6.0 m/s²

t = 4.0 s

Find: v

v = at + v₀

v = (-6.0 m/s²) (4.0 s) + 40 m/s

v = 16 m/s