Answer:
0.667 m/s^2
Explanation: Given that you slow down from 2m/s to a stop 3s.
Using first law of motion.
V = U - at
Where
Final velocity V = 0
Initial velocity U = 2 m/s
Time taken t = 3 seconds
Since the body slow down, the final velocity V will be equal to zero. And the acceleration will be negative.
Substitute all the parameters into the formula
0 = 2 - a × 3
3a = 2
a = 2 /3
a = 0.667 m/s^2
Therefore, your acceleration during this time interval will be 0.667 m/s^2
