how do you solve this
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Answer:
4x^-4/9y^6
Step-by-step explanation:
If the exponent is outside the bracket, it means that all the terms inside will be raised to that exponent. This means that:
(2x^-2 / 3y^3)^2 = 2^2*(x^-2)^2 / 3^2*(y^3)^2
When exponents are raised to an exponent, the exponents are multiplied together, so (x^-2)^2 will = x^(-2*2) = x^-4
Going through:
2^2*(x^-2)^2 / 3^2*(y^3)^2
=4*x^-4 / 9*y^6
=4x^-4/9y^6
Hope this helped!