Answer:
distance =
[tex] \sqrt{ \frac{10}{3} } [/tex]
Step-by-step explanation:
Without going through and deriving this (my blackboard doesn't have space and a textbook, teacher, or online tutorial is probably better for that), the equation for the distance from some point on the plane to some point in space is as follows:
[tex]distance = \frac{ax + by + cz - d }{ \sqrt{ {a}^{2} + {b}^{2} + {c}^{2} } } [/tex]
•Note that the d in the equation should actually be D but Brainly doesn't allow me to do uppercase letters on mobile it seems... Anyway, d in the equation represents the value which the equation of the plane is equal to. You only gave the plane equation so I assumed d=0 in my calculations.
•x, y, and z all come from the point which you want to find the distance to. So (x,y,z)=(0,4,3) here.
•a, b, and c all come from the components of the vector normal to the surface. For planes, it simply somes to be the coefficients in front of each part. So (a,b,c)=(5,1,2) here.
With that you just need to plug the information in and simplify for your answer. My work is in the attachment, comment with questions or if anything seems off.
