Question

given the following functions f(x) and g(x), evaluate (gºf)(-2). Enter answer.
f(x)=2x^2+2x-5
g(x)=-1/-4x+6​

Answer 1

Answer:

the composition results in $\frac{23}{4}$

Step-by-step explanation:

Assuming that what you typed for function g is correct (looks a bit peculiar, but we will use it as typed):

$g(x)=-\frac{1}{-4x} +6$

gof(-2) can be understood as: g(f(-2)), so what we need to do is to find the value for f(-2) using its given expression, and using then the obtained value as input for g(x):

$f(x)=2x^2+2x-5\\f(-2)=2\,(-2)^2+2\,(-2)-5\\f(-2)= 8-4-5\\f(-2)= -1$

So, we now evaluate g(-1):

$g(x)=-\frac{1}{-4x} +6\\g(-1)= -\frac{1}{-4(-1)} +6\\g(-1)= -\frac{1}{4} +6\\g(-1)=\frac{23}{4}$